Factor 18v⁹+33v⁸+14v⁷ completely
1 answer:
Answer:
x (6v+7) x (3v+2)
Step-by-step explanation:
18v^9 + 33v^8 +14v^7
Factor out v^7 from the expression
v^7 x (18v^2+33v+14)
write 33v as a sum
v^7 x (18v^2+21v+12v+14) *like this 21v+12v
Factor out 3v from the expression
v^7 x (3v x (6v+7)+12v+14)
Factor out 2 from the expression
c^7 x (3v x (6v+7)+2(6v+7)
Factor out 6v+7 from the expression
v^7 x (6v+7) x (3v+2)
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Check the picture below.
so, that'd be 20.24845673131658693325, and to the nearest tenth it'd then be 20.2
so, that'd be 20.24845673131658693325, and to the nearest tenth it'd then be 20.2
Answer:
The sum of the arithmetic sequence is .
Step-by-step explanation:
A sequence is a set of numbers that are in order.
In an arithmetic sequence the difference between one term and the next is a constant. In other words, we just add the same value each time infinitely.
If the first term of an arithmetic sequence is and the common difference is d, then the nth term of the sequence is given by:
For the sequence
The pattern is continued by adding -11 to the last number each time.
An arithmetic series is the sum of an arithmetic sequence. We find the sum by adding the first, and last term,
, divide by 2 in order to get the mean of the two values and then multiply by the number of values, <em>n</em>
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The sum of the arithmetic sequence is