4. To determine if a triangle is a right triangle, given that you know the length of its sides, you have to check if its lengths follow the Pythagorean theorem.
This theorem states that the square of the hypothenuse (c) is equal to the sum of the squares of the legs of the triangle (a and b), following the expression:
The triangle is:
We have to check that a²+ b² is equal to c².
The square of the hypothenuse is:
The sum of the squares of the legs of the triangle is:
As you can see, the sum of the squares of the legs of the triangle is 100, which is the same as the square of the hypothenuse. The triangle follows the Pythagorean theorem and can be considered a right triangle.
It would be -12.75 because it is the opposite of 12.75
Answer:
We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:
For this case we have that:
And we see that 
So then we can conclude that the two events given are not independent and have a relationship or dependence.
Step-by-step explanation:
For this case we can define the following events:
A= In a certain computer a memory failure
B= In a certain computer a hard disk failure
We have the probability for the two events given on this case:
We also know the probability that the memory and the hard drive fail simultaneously given by:
And we want to check if the two events are independent.
We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:
For this case we have that:
And we see that
So then we can conclude that the two events given are not independent and have a relationship or dependence.
Answer:
Left on the x-axis
Step-by-step explanation:
The opposite of the coefficient's amount of units is how much the graph will be moved.
Table comparisons
g(x)=|x+4|
x 1 -2 <u>-4</u>
y 5 2 <u>0</u>
Underlined is the x-int of the equation.
f(x)=|x|
x 1 <u>0</u> -1 3
y 1 <u>0</u> 1 3
