Question

A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard, which is 40 feet by 65 feet. If a neighbor’s yard is 50 feet by 80 feet, what would the neighbor be charged based on how much Mr. Jones was charged?

Answer 1

Answer:

Landscaping Company will charge $80 for Neighbor yard.

Step-by-step explanation:

Given:

Charges of Mr. Jones = $52

Length of Mr. Jones yard = 65 feet

Width of Mr. Jones yard = 40 feet

Now we will find the area of Mr. Jones yard.

Yard is basically in rectangular form.

Hence we can;

Area of yard is equal to product of length of the yard and width of the yard.

Framing in equation we get;

Area of Mr. Jones Yard = $40\times 65 = 2600\ ft^2$

Now Mr. Jones was charged $52 for a yard having Area 2600 sq. ft.

So we will find the per sq. ft charge applied by the company.

Per sq. ft charge will be equal to Charges of Mr. Jones divided by Area of Mr. Jones Yard.

Framing in equation form we get;

Per sq. ft charge = $\frac{52}{2600} = \ 0.02$

Hence the Landscaping company charge Mr. Jones at $0.02 per sq.ft.

Now Given:

Length of Neighbor yard = 80 ft.

Width of Neighbor yard = 50 ft.

We need to find the Charges on Neighbor based on charges applied on Mr. Jones.

First we will find the Area of Neighbors yard we get;

Area of Neighbors yard = $80 \times50 = 4000\ ft^2$

Charges of Neighbor yard will be equal to charges Landscaping company for per sq. ft multiplied by area of Neighbors yard.

Framing in equation form we get;

Charges of Neighbor yard = $0.02\times 4000 = \ 80$

Hence Landscaping Company will charge $80 for Neighbor yard.