Answer:
y = 100°
Step-by-step explanation:
I can't see the full question, but I'm guessing you need to find the measure of angle y.
The total angle sum of a polygon can be calculated with the formula
T = 180°(n - 2) where T is the total angle measure, and n i the number of sides.
For our shape, there are 4 sides, so n = 4. Plug that in and simplify...
T = 180°(4 - 2)
T = 180°(2)
T = 360°
We are given 3 of the angles, so angle y is
y = 360 - 107 - 104 - 49
y = 100°
Answer:
50 cents
Step-by-step explanation:
half of 5.00$ is 2.50$
One question, are they congruent figures?
Hmm I’ve done this before but I can’t remember sorry but I will try and think
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
