<img src="https://tex.z-dn.net/?f=%28a%29%20%7B%20-%20%28b%29%7D%5E%7B2%7D%20" id="TexFormula1" title="(a) {

All categories

CaHeK987 [17]

2 years ago

a) { - (b)}^{2} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Cloud [144]2 years ago

7 0

Answer:

a - b2

Step-by-step explanation:

STEP 1 :

Trying to factor as a Difference of Squares:

1.1 Factoring: a-b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : a1 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :

a - b2

HOPE THIS HELPS!

PLEASE MARK BRAINLIEST! :)

You might be interested in

Identify the population and sample.

iris [78.8K]

Population is 200 and sample is 30

Thank you hope this helps

3 0

3 years ago

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

2 years ago

Question 9 (10 points) Solve for x, 2(x - 1) + 4 = 4(x + 1)

Nutka1998 [239]

1. Expand
2x − 2 + 4 = 4x + 4

2. Simply
2x + 2 = 4x + 4

3. Subtract
2 = 4x + 4 - 2x

4. Simplify
2 = 2x + 4

5.Subtract
2 - 4 = 2x

6. Simplify
-2 = 2x

7. Divide both sides by
-1 = x

8.Switch sides.
x = -1

6 0

3 years ago

Write an equation in Slope-Intercept Form using the table below.

Veseljchak [2.6K]

Answer:

y = x + 46

Step-by-step explanation:

When writing an equation of a line, keep in mind that you always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, choose two pairs of coordinates to use for solving the slope of the line:

Let (x1, y1) = (0, 46)

(x2, y2) = (1, 47)

User the following formula for slope

$m = \frac{y2 - y1}{x2 - x1}$

Plug in the values of the coordinates into the formula: $m = \frac{y2 - y1}{x2 - x1} = \frac{47 - 46}{1 - 0} = \frac{1}{1} = 1$

Therefore, the slope (m) = 1.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, 46) is the y-intercept. Therefore, b = 46.

Given the slope, m = 1, and y-intercept, b = 46, the linear equation in slope-intercept form is:

y = x + 46

Please mark my answers as the Brainliest if you find my explanations helpful :)

8 0

2 years ago

If AC=12, BC=3, find CE 1) 3 square root of 3 2) 6 3) 18

azamat

Answer:

2) 6

Step-by-step explanation:

CE^2 = BC * AC

CE^2 = 3 * 12

CE^2 = 36

CE = 6

7 0

2 years ago

Read 2 more answers