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pentagon [3]
3 years ago
10

I WILL HAVE ORDER╲ ╲

Mathematics
2 answers:
Scrat [10]3 years ago
8 0

sorry what?

Step-by-step explanation:

I Don't understand

bezimeni [28]3 years ago
3 0

Answer:

//

Step-by-step explanation:

I threw them right back at you cause where's the problem???

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dem82 [27]
I want to say The surface area of the prism is A
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3 years ago
Find the domain and range of the function f(x) = 3x^2 - 5.Also find f(-3) and the numbers which are associated with the number 4
Delicious77 [7]

Domain:


This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: D = \mathbb{R}


Range:


A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like [a,\infty). To find the minimum, let's start with the "standard" parabola y=x^2, and transform it to the one of this exercise. y=x^2 has minimum 0, and thus its range is [0,\infty). When you multiply it times three, its shape narrows, but the range wont change: [0,\infty) \to [3\cdot 0,3\cdot \infty) = [0,\infty). Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have [0,\infty) \to [0-5,\infty-5) = [-5,\infty)


Image of -3:


To compute f(-3), simply plug x=-3 in the formula:


f(-3) = 3(-3)^2-5 = 3\cdot 9 - 5 = 27-5 = 22


Numbers associated with 43:


We want to see which x value we must choose to get a y value of 43. So, the equation is


y = 3x^2-5 \to 43 = 3x^2-5 \iff 48 = 3x^2 \iff 16 = x^2 \iff x = \pm\sqrt{16} = \pm4

4 0
3 years ago
After he completed his graduate work, he became a professor at
Lisa [10]
University of California, Berkley
6 0
4 years ago
A train leaves at 11.15 and arrives at its destination at 12.23. If the train travelled 95 km, what was it's average speed in km
xxMikexx [17]

Answer:

Average speed v = 83.8 km/h

Step-by-step explanation:

Given;

Distance travelled = 95 km

Time taken t = 12.23 - 11.15 = 1 hour 8 minutes

t = 1 + 8/60 hours = 1.133 hours.

Average speed v = distance travelled/time taken

substituting the values;

v = 95 km ÷ 1.133 hours

Average speed v = 83.8 km/h

4 0
3 years ago
A total of 327 tickets were sold for the school play. they were either adult tickets or student tickets. the number of student t
olga55 [171]
218 Students
109 Adults

Let x = adults
Let 2x = students

Add together and set equal to the total number. 
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3 years ago
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