----------------------------------------------------
Define the numbers
----------------------------------------------------
Let the first even number be x
1st even number = x
2nd even number = x + 2
3rd even number = x + 4
----------------------------------------------------
Form the equation and solve
----------------------------------------------------
x + x + 2 + x + 4 = -6
3x + 6 = -6
3x = - 12
x = -4
----------------------------------------------------
Find the numbers
----------------------------------------------------
1st even number = x = -4
2nd even number = x + 2 = -4 + 2 = -2
3rd even number = x + 4 = -4 + 4 = 0
----------------------------------------------------
Answers: The numbers are -4, -2 and 0
----------------------------------------------------
Answer: 720
Step-by-step explanation: if what you want are all possible three digit numbers with no repetition of the digits then you have 10 choices for the first digit, you have 9 choices for the 2nd digit, and you have 8 choices for the 3rd digit giving you 10x9x8 = 720 in all.
2(x + 6) is what you’re looking for. Have a good day!
Example
from pir^2 ro pi(2r)^2
pi(2r)^2=pi4r^2=4pir^2
basicaly we look for any no options and ones where second is 4 times first
B
pi2^2, if it is double, pi4^2
B
