3 years ago

Can you help me please (get brainliest)

Mathematics

1 answer:

marta [7]3 years ago

6 0

9514 1404 393

Answer:

4/25

Step-by-step explanation:

Put the numbers where the letters are and do the arithmetic.

$\left(2\cdot\dfrac{-1}{2}\cdot\dfrac{2}{5}\right)^2=\left(\dfrac{-2}{5}\right)^2=\dfrac{(-2)^2}{5^2}=\boxed{\dfrac{4}{25}}$

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What are the domain and range of the function?<br> f(x) = ^3 square x - 3

DerKrebs [107]

Step-by-step explanation:

$f(x) = \sqrt[3]{x - 3}$

The domain of a function are the values of $x$ that you can plug into the function $f(x)$ .

Values inside of a root must be non-negative, which means that $x - 3$ must be greater than or equal to zero. We can set up an equation to find the domain:

$x - 3 \geq 0$

$x \geq 3$

With this, we know the domain of the function is $[3, \inf)$ .

The range of a function are the values that $f(x)$ can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is $[0, \inf)$ .