Answer:
The bulbs should be replaced each 1060.5 days.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?
This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.
The bulbs should be replaced each 1060.5 days.
Answer:
69x420=28,980
Step-by-step explanation:
i will
Answer: $187 will be in the account after 6 years.
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $100
r = 11% = 11/100 = 0.11
n = 1 because it was compounded once in a year.
t = 6 years
Therefore,.
A = 100(1 + 0.11/1)^1 × 6
A = 100(1 + 0.11)^6
A = 100(1.11)^6
A = $187
Answer:
(- 7, - 3) and (7, - 3)
Step-by-step explanation:
The best way to do this is to sketch the graph...when dealing with reflection in the y axis, the value for y remains the same and the value for x becomes negative if it was positive or becomes positive if it was negative
The answer is (-2, -3) since 2*-2–(+)3= -1 and 2*-2-4*-3= 8.
