500 cubic feet of 1/2-inch thick stainless steel plates will weigh the same no matter what dimensions are use for area and height of tank.
A 5 foot by 5 foot area 20 feet high (500 cubic feet) will weigh just as much as a 10 foot by 10 foot area 5 feet high (also 500 cubic feet) since you are using the same amount of material for the whole tank. Only possible change in weight of tank is the use of welding material and how evenly and good the welder is at welding stainless steel.
slope = (y2-y1)/(x2-x1)
m =(17-4)/(8-1)
m = 13/7
You have to keep the pairs in the same order
Answer:
ion know
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The angle at the circumference b , is half the angle subtended at the centre by the arc XZ, that is
b = 0.5 × 72 = 36
OZ and OX are congruent ( both radii of the circle )
Thus Δ OXZ is isosceles with base angles congruent, thus
a =
=
= 54
∠ XZY = 90° ( angle in a semicircle is right )
I find the problem confusing because it forces a certain sequence of thought process, and I find I get way beyond these questions and answers rather quickly. I would start with the equation of part B, having already recognized the conversions of percent to decimal and the need to make the acid quantities add up. Doing the problem a different way gets you to the answer in part C without any of these "steps," so going back and trying to fill in the "steps" seems awkward, at best.
Perhaps the attachment here helps.