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Wittaler [7]
3 years ago
13

A box shaped like a rectangular prism has a height of 4 feet, a length of 10 feet, and a width of 6 feet. The box is filled with

chocolate coins that weigh an average of 0.01 pound per cubic foot. What is the total weight of the chocolate coins in the box?
Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:44coins

Step-by-step explanation:

idds

Ksivusya [100]3 years ago
7 0

Answer:

2.4 pounds.

Step-by-step explanation:

The volume of the box = 4*6*10 =  240 cu ft.

So the weight of the coins = 240 + 0.01

= 2.4 pounds.

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Determine all critical points the the function:
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7 0
3 years ago
According to the Oxnard College Student Success Committee report in the previous year, we believe that 18% of students struggle
gladu [14]

Answer:

A sample size of 392 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

18% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class.

This means that \pi = 0.18

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

You would like to be 99% confident that your estimate is within 5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.05. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.05 = 2.575\sqrt{\frac{0.18*0.82}{n}}

0.05\sqrt{n} = 2.575\sqrt{0.18*0.82}

\sqrt{n} = \frac{2.575\sqrt{0.18*0.82}}{0.05}

(\sqrt{n})^2 = (\frac{2.575\sqrt{0.18*0.82}}{0.05})^2

n = 391.5

Rounding up:

A sample size of 392 is required.

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atroni [7]

Answer:

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7 0
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The answer is idk bc i don't know

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3 years ago
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