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SSSSS [86.1K]
3 years ago
15

One card is selected at random from a deck of cards. Determine the probability that the card selected is a card greater than 3 a

nd less than 8.
Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

4/13

Step-by-step explanation:

Count all cards that are 4, 5, 6, and 7 (each of 4 different suits) so the number of cards that is greater than 3 and less than 8 = 4(4) = 16.

There are 52 cards in a standard deck of cards.

P(greater than 3 and less than 8)

= 16/52

= 4/13

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Answer:

A first one: 5-9

Step-by-step explanation:

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Zigmanuir [339]

Answer:

Step-by-step explanation:

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Three brothers, Justin, Jared, and Jonathan decided to buy a present for their mom's birthday. Justin gave decided to spend 1/4
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I believe that, if there are three brothers and each invested the same exact money to make a total of $33.00, each brother would have invested $11.

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3 years ago
Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

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Let's use elimination method, multiply the equation a by -2:

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<span>2x – 3y – 2z = 4 
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2x+6=4

2x=-2

x=-1

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Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
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