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atroni [7]
1 year ago
5

$10,000 for 5 years at 4% interest

Mathematics
1 answer:
inessss [21]1 year ago
3 0

Simple interest earned on the principal amount $10,000 for 5 years at 4% interest per year will be $12,000.

As given in the question,

Simple Interest:

The simple interest is an amount that is paid for loan or borrowed money over a certain period at a fixed percentage of borrowed money.

Principal amount:

Principal amount is the money that is taken as loan or borrowed.

Formula of Simple Interest:

Simple interest = Principal amount × Rate × Time

Since,

Principal amount = $10,000

Rate = 4% per year

Time = 5 years

Then,

Simple interest = 10,000 × 4 × 5

Simple interest = $ 12000

Total value after 5 years = $ 12000

Principal amount = $ 10000

Interest Earned = (Total value) - (Principal amount)

Interest Earned = $ 12000 - $ 10000

Interest Earned = $ 2000

Therefore, simple interest earned on the principal amount $10,000 for 5 years at 4% interest per year will be $12,000.

The complete question is:

Fabian is taking out a loan in the amount of $10,000. His choices for the loan are a 5-year loan at 4% rate of interest .What is the amount of simple interest and interest earned Fabian would have to pay?

To know more about simple interest here

brainly.com/question/25845758

#SPJ1

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Answer:

3/17

Step-by-step explanation:

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4 0
2 years ago
Exam​ question: You can buy a 57​-pound bag of flour for ​$ 11 or you can buy a​ 1-pound bag for $ 0.41 Compare the per pound co
egoroff_w [7]

Answer:

Step-by-step explanation:

57 lb bag for $ 11  or 1 lb bag for $ 0.41

11/51 = 0.215 .....rounds to 0.22 ......this is the correct way...... the student messed up and divided wrong.

the large bag only charges $ 0.22 per lb, whereas, the small bag charges $ 0.41 per lb.

3 0
4 years ago
during their last game a football team lost a total of 12 yards on three consecutive plays. They lost the same number of yards o
Paha777 [63]

Answer:

Theres 4 yards each play,

Step-by-step explanation:

6 0
3 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
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