Answer:
A 2-column table with 6 rows. Column 1 is labeled x with entries 1.99, 1.999, 1.9999, 2.0001, 2.001, 2.01. Column 2 is labeled f (x) with entries 0.505, negative 0.827, 0.306, negative 0.306, 0.827, negative 0.506.
Find Limit of f (x) as x approaches 2 f(x), if it exists.
2
0.3
0
DNE
Step-by-step explanation:
divide 417.12 by 23.7, and get your answer: <u>17.6</u>
Answer:
70 members in 2016
Step-by-step explanation:
In 2016
Let the number of members= x
They all paid y amount
Total fees= 42
Xy= 42...... equation 1
In 2017
Members= x+20
They paid y-0.1
Total fees = 45
(X+20)(y-0.1)= 45…equation 2
Xy -0.1x +20y -2= 45
Using values from equation 1
42-0.1(42/y) +20y -2= 45
-4.2/y+20y-5= 0
20y² -4.2 -5y = 0
100y² -25y -21= 0
Solving quadratically
Y= 0.6 or -0.35
We are dealing with price so y Is
definitely a positive number
Y= 0.6
If y= 0.6
Solving for x
Xy= 42
X= 42/0.6
X=70
There were exactly 70 members in 2016
3.5 or 4 if you can only get 4 pound bags. Hope this helps!
