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marin [14]
3 years ago
10

What is the first step in evaluating the expression shown below? (12.9-3.1) 6.2-2 + 43

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

Subtract 3.1 from 12.9

Hope it helped

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Please help me with this trigonometry question:
zzz [600]

Answer:

The distance from A to B is 736.2 to the nearest tenth foot

Step-by-step explanation:

In ΔCAB

∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A

∴ m∠CAD = m∠ACB + m∠ABC

∵ m∠ABC = 20°

∴ m∠ACB = 30° - 20° = 10°

We will use the sin rule to find the distance AB

∵ \frac{sin20}{1450}=\frac{sin10}{AB}

∴ AB=\frac{1450(sin10)}{sin20}=736.1842936 ≅ 736.2 to the nearest tenth foot

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2 years ago
5y + 3 > −7y + 13 Multi-step linear inequalities
Artemon [7]

Answer:

y > \frac{5}{6}

Step-by-step explanation:

Given

5y + 3 > - 7y + 13 ( add 7y to both sides )

12y + 3 > 13 ( subtract 3 from both sides )

12y > 10 ( divide both sides by 12 )

y > \frac{10}{12} , that is

y > \frac{5}{6}

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3 years ago
The volume of a cube is 7.14 cubic meters. What is the cross-sectional area that is parallel to one of its faces?
Snowcat [4.5K]

Answer:

A = 3.706 square meters

Step-by-step explanation:

the length of a cube has equal side.

therefore, the volume of a cube is given by S³

V = S³ = 7.14

where S is the length of a side

the surface area of a cube is = 6S²

where the area a aside is calculated, then it is multiply by 6.

if S³ = 7.14

S = ∛(7.14) = 1.925 m

What is the cross-sectional area that is parallel to one of its faces?

this is saying we should calculate for the cross-sectional area of one face. All faces in a cube is equal and parallel to each other.

the crossectional  area of one side of a cube is = S² = 1.925² = 3.706 square meters

A = 3.706 square meters

8 0
3 years ago
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