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kompoz [17]
2 years ago
8

Joe’s Plumbing and Mark’s Plumbing have different ways of charging their customers. The function defined by J(t)=45t represents

the total amount in dollars that Joe’s Plumbing charges for t hours of work. Mark’s Plumbing charges $40 per hour plus a $25 trip charge.
Mathematics
1 answer:
Reptile [31]2 years ago
5 0

Answer:

that is a very good question sir

Step-by-step explanation:

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Use complete sentences explain whether the following scenario will display biased results. A power plant measures its emissions
LekaFEV [45]
The location of the sensor that it is opposite the direction of the wind is reasonable and is needed to identify the plant's emissions. However, there might be a bias to that if it is located a mile from the plant's smokestack. The distance may be quite far. Considerations in identifying the location of the sensors such as changes in wind direction, wind speed, atmospheric stability, physical stack height, diameter, and other important factors are needed to have an accurate reading of the pollutants.
4 0
3 years ago
the odometer in Mr Washington's car does not work correctly the odometer recorded 13.2 miles for his last trip to the hardware s
Nonamiya [84]
12 percent is the error.
3 0
3 years ago
Find the value of c such that y= x + c is a tangent to the parabola y = x squared - x - 12
Bond [772]

Answer:

c = –13

Step-by-step explanation:

by property of tangent line, equation

x² – x – 12 = x + c

x² – 2x – 12 – c = 0

has only one solution, which mean

– 12 – c = 1

c = –13

5 0
3 years ago
What is the equation of a line with a slope of 2 and a y-intercept of -5?
RSB [31]
Y=2x-5

Hope this helps ya :D
7 0
2 years ago
Joey invest $900 at 4% simple interest for 2 years but he wants to know how much money he will have after only 18 months. Determ
malfutka [58]
Well, bearing in mind that, a year has 12 months, so 18 months is really just 18/12 of a year, or 3/2 a year, then

\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$900\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to \frac{18}{12}\to &\frac{3}{2}
\end{cases}
\\\\\\
A=900\left( 1+0.04\cdot \frac{3}{2} \right)
4 0
3 years ago
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