Answer:
C) 4
Step-by-step explanation:
I hope this helps :)
Answer:
<em>Most likely time, </em>according to PERT (Program evaluation and review technique).
Step-by-step explanation:
PERT is "a statistical tool used in <em>project management" (Program evaluation and review technique (2020), </em>in Wikipedia), and it is commonly used with CPM <em>(Critical Path Method)</em> to manage projects.
Inside PERT, there are different defined times to accomplished an activity in a project, that is:
- An <em>optimistic time</em> or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
- A <em>pessimistic time, </em>a time quite the opposite to optimistic time.
- A <em>most likely time</em>, or a time required to accomplished an activity if everything goes as expected or normally.
- An <em>expected time</em>, an statistical estimation.
Considering the question, we have that the <em>time</em> when "the first module of the project could be completed":
- "[...] in as few as 15 days" is the <em>optimistic time</em>.
- "[...] or could take as many as 25 days" is the <em>pessimistic time</em>.
- "[...] but most likely will require 20 days" is the <em>most likely time</em>.
As a result, the <em>20-day estimate</em> is called the <em>most likely time</em> in the context of the PERT/CPM techniques.
For the transformation
the Jacobian is
with determinant
The vertices of the triangle in the 
-plane are
Then the integral is
Answer:
0.345
Step-by-step explanation:
Use binomial probability:
P = nCr pʳ qⁿ⁻ʳ
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1−p).
n = 5, r = 2, p = 0.41, and q = 0.59.
P = ₅C₂ (0.41)² (0.59)⁵⁻²
P = 0.345
