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GarryVolchara [31]
3 years ago
15

- ALGEBRA In the figure, line m is

Mathematics
1 answer:
Ilya [14]3 years ago
4 0
The measurement would be equal because they are opposite angles with same degree. If solving for x it is 10 but otherwise the line p runs through and separates so p is the answer. Lmk if this helped!
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The Nike store is having a SALE!!! A toddler suit with an original cost of $54 is marked down to $22.95. How much is the discoun
pishuonlain [190]

Answer:

The Discount Percent is 57.50% and the Discount Amount is $31.05

Step-by-step explanation:

To find the discount percent you use the formula D = (L - S) / L x 100. To find the discount amount you take the <u>inital list price</u> and subtract it from the <u>sale price</u>.

4 0
3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
More help need 50 points
Sergio039 [100]
50p-40p+25-p
9p+25 is the answer.
8 0
1 year ago
Read 2 more answers
Determine whether the conjecture is true or false. Give a counterexample for any false conjecture.
AnnyKZ [126]

Answer:

The Answer is C. false; m =-2 or m=2

Step-by-step explanation:

This is because:

2*2=4 being 4+6=10 Making 2 true, but

-2*-2= 4 as well making it 4+6=10, Making -2 true as well.

6 0
3 years ago
Read 2 more answers
4. A book club earns $230 for its meetings. They want to divide the money to pay for 7 meetings. When the treasurer types 230 ÷
DIA [1.3K]

Answer:

to the tenths place, 32.86

Step-by-step explanation: It is because money is always rounded to the tenths place

4 0
3 years ago
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