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2 years ago

Skeletal muscle is controlled by the organism.

Biology

1 answer:

Alexandra [31]2 years ago

7 0

Answer:

Voluntary

Explanation:

Because some of the muscle attached to the skeleton is voluntary

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what is the difference between the closed conformation and open conformation of chromatin packing? biology

Oduvanchick [21]

The shape of chromatin, which can be either open (euchromatin) or compact (heterochromatin), is dynamically regulated during the phases of the cell cycle is the two types of conformations.

The main distinction between conformation and configuration is that whereas the configurations of the same molecule do not easily interconvert, their conformations do.
With a predefined location in the nucleus and a certain form, such as metacentric, submetacentric, acrocentric, or telocentric, chromosomes are primarily heterochromatic in this stage.
All DNA-mediated processes, including gene regulation, can be significantly impacted by the degree of nucleosomal packaging.
While heterochromatin (tight or closed chromatin) is more compact and resistant to factors that need to access the DNA template, euchromatin (loose or open chromatin) structure is permissible for transcription.

To know more about chromatin check the below link:

brainly.com/question/691971

#SPJ4

5 0

1 year ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

4 0

2 years ago

Which statements about plant and animal cells is true?

erma4kov [3.2K]

Plants have a cell wall and chloroplasts; animal cells do not have either

Hope this helps : )

6 0

2 years ago

How does interaction with birds help a flowering plant?

AlladinOne [14]

I think it is A because birds do help spread around the seeds hope i helped

3 0

2 years ago

Read 2 more answers

Kingdom Animalia:

Mice21 [21]

Answer:

Eukaryotic

Prokaryotic

Unicellular

Multicellular

Autotrophic

Heterotrophic

Explanation:

-organism having nucleus

-organism without nucleus

-organism having one cell

-organism having many cell

-Organism that can make their own food

-Organism that cannot make their own food.

4 0

3 years ago