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3 years ago

10 people in a room each person shakes hands with every other person in the room exactly once how many handshakes will there be

Mathematics

2 answers:

Elena L [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Since it is every other person the answer upon me is 50

Alex73 [517]3 years ago

4 0

There will be 100 hand shakes because you would do 10x10 which is 100

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Prove the following integration formula:

7nadin3 [17]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Distributive Property
Equality Properties

Algebra I

Combining Like Terms
Factoring

Calculus

Derivative 1: $\frac{d}{dx} [e^u]=u'e^u$
Integration Constant C
Integral 1: $\int {e^x} \, dx = e^x + C$
Integral 2: $\int {sin(x)} \, dx = -cos(x) + C$
Integral 3: $\int {cos(x)} \, dx = sin(x) + C$
Integral Rule 1: $\int {cf(x)} \, dx = c \int {f(x)} \, dx$
Integration by Parts: $\int {u} \, dv = uv - \int {v} \, du$
[IBP] LIPET: Logs, Inverses, Polynomials, Exponents, Trig

Step-by-step Explanation:

Step 1: Define Integral

$\int {e^{au}sin(bu)} \, du$

Step 2: Identify Variables Pt. 1

Using LIPET, we determine the variables for IBP.

Use Int Rules 2 + 3.

$u = e^{au}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = sin(bu)du\\du = ae^{au}du \ \ \ \ \ \ \ \ \ v = \frac{-cos(bu)}{b}$

Step 3: Integrate Pt. 1

Integrate [IBP]: $\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} - \int ({ae^{au} \cdot \frac{-cos(bu)}{b} }) \, du$
Integrate [Int Rule 1]: $\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{a}{b} \int ({e^{au}cos(bu)}) \, du$

Step 4: Identify Variables Pt. 2

Using LIPET, we determine the variables for the 2nd IBP.

Use Int Rules 2 + 3.

$u = e^{au}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = cos(bu)du\\du = ae^{au}du \ \ \ \ \ \ \ \ \ v = \frac{sin(bu)}{b}$

Step 5: Integrate Pt. 2

Integrate [IBP]: $\int {e^{au}cos(bu)} \, du = \frac{e^{au}sin(bu)}{b} - \int ({ae^{au} \cdot \frac{sin(bu)}{b} }) \, du$
Integrate [Int Rule 1]: $\int {e^{au}cos(bu)} \, du = \frac{e^{au}sin(bu)}{b} - \frac{a}{b} \int ({e^{au} sin(bu)}) \, du$

Step 6: Integrate Pt. 3

Integrate [Alg - Back substitute]: $\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{a}{b} [\frac{e^{au}sin(bu)}{b} - \frac{a}{b} \int ({e^{au} sin(bu)}) \, du]$
[Integral - Alg] Distribute Brackets: $\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2} - \frac{a^2}{b^2} \int ({e^{au} sin(bu)}) \, du$
[Integral - Alg] Isolate Original Terms: $\int {e^{au}sin(bu)} \, du + \frac{a^2}{b^2} \int ({e^{au} sin(bu)}) \, du= \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}$
[Integral - Alg] Rewrite: $(\frac{a^2}{b^2} +1)\int {e^{au}sin(bu)} \, du = \frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}$
[Integral - Alg] Isolate Original: $\int {e^{au}sin(bu)} \, du = \frac{\frac{-e^{au}cos(bu)}{b} + \frac{ae^{au}sin(bu)}{b^2}}{\frac{a^2}{b^2} +1}$
[Integral - Alg] Rewrite Fraction: $\int {e^{au}sin(bu)} \, du = \frac{\frac{-be^{au}cos(bu)}{b^2} + \frac{ae^{au}sin(bu)}{b^2}}{\frac{a^2}{b^2} +\frac{b^2}{b^2} }$
[Integral - Alg] Combine Like Terms: $\int {e^{au}sin(bu)} \, du = \frac{\frac{ae^{au}sin(bu)-be^{au}cos(bu)}{b^2} }{\frac{a^2+b^2}{b^2} }$
[Integral - Alg] Divide: $\int {e^{au}sin(bu)} \, du = \frac{ae^{au}sin(bu) - be^{au}cos(bu)}{b^2} \cdot \frac{b^2}{a^2 + b^2}$
[Integral - Alg] Multiply: $\int {e^{au}sin(bu)} \, du = \frac{1}{a^2+b^2} [ae^{au}sin(bu) - be^{au}cos(bu)]$
[Integral - Alg] Factor: $\int {e^{au}sin(bu)} \, du = \frac{e^{au}}{a^2+b^2} [asin(bu) - bcos(bu)]$
[Integral] Integration Constant: $\int {e^{au}sin(bu)} \, du = \frac{e^{au}}{a^2+b^2} [asin(bu) - bcos(bu)] + C$

And we have proved the integration formula!

6 0

3 years ago

Read 2 more answers

Based on the spreadsheet below, which of the following is a true statement? A 2-column spreadsheet showing Cash Inflows and Cash

timama [110]

The net cash flow which is the excess of inflows over outflows is $110, hence, the correct option is:

c. The net cash flow is positive

What are inflows and outflows?

The inflows are cash received by the individual which increase cash balance where cash outflows are expenses, which reduce the balance of cash.

Based on the above, the total inflows of the individual is computed thus:

total inflows=disposable income+ interest on deposit +income from investment

total inflows=1600+0+0

total inflows=$1,600

Total outflows are as well summed as below:

total outflows=rent +utilities +cable and telephone +groceries+ car expenses+ recreation+ insurance + miscellaneous

total outflows=575+120+80+320+150+80+115+50

total outflows=$1,490

net cash flow=total inflows-total outflows

net cash flow=$1,600-$1,490

net cash flow=$110

Find out more about inflows and outflows on brainly.com/question/28356638

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8 0

2 years ago

Read 2 more answers

About 1.2 million people live in a region with a 6-mile radius what is the population destiny in people per square mile

Paladinen [302]

Answer:

10616 people per square mile

Step-by-step explanation:

No. of people living in the region = 1.2 million

Radius of the area = 6 mile

Since radius of region is given, area of can be calculated by using formula to get area of circle which is $\pi r^2$ where r is radius of circle.

the value of pie is 3.14 which will be used in the calculation

Area of region

$\pi r^2 \\=> 3.14 * 6^2\\=> 113.04$

population density of any place is calculated by dividing the total population of region with area of the region

mathematically it can be written as

population density of any place = the total population of region / area of the region

substituting the value of total population of region with 1.2 million and area of the region as calculated 113.04 square mile we have

population density of any place = 1.2 million/113.04 square mile

= 0.0106157113 million / square mile

Since one million is equal to 1,000,000

0.0106157113 million will be equal to 0.0106157113 * 1,000,000

= 10615.7113

rounding 10615.7113 nearest to unit value, it will be 10616.

Therefore, population density is 10616 people per square mile.

3 0

4 years ago

If two fair dice are rolled, what is the probability that the total showing is either even or less than nine?

Gemiola [76]

Answer:

1/2 and 13/18 respectively

Step-by-step explanation:

even-number results:

2, 4 6 ,8, 10 and 12

the combinations of each result are respectively

1+3+5+5+3+1 = 18

The total number of combinations on a roll pair is 36

then the probability of obtaining an even result is:

p = 18/36 = 1/2 or 0.5

so that the result is less than nine, we eliminate the combinations of results 9, 10, 11 and 12:

4 + 3 + 2 + 1 = 10

36 -10 = 26

the probability of obtaining a result less than nine is:

p = 26/36 = 13/18 or 0.72

Hope this helps

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2 years ago

A dishwasher salesman whose base pay plus commissions amount to $30,605 last year earned a commission of 12.5% on each dishwashe

ASHA 777 [7]

Its is d 14 hdhdhshajhscddvffbff

7 0

3 years ago

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