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ser-zykov [4K]
2 years ago
13

Find the surface area of the rectangular prism

Mathematics
2 answers:
mezya [45]2 years ago
8 0

Answer:

<h2>S.A. = 328</h2>

Step-by-step explanation:

The formula of a surface area of a rectangular prism l × w × h:

S.A.=2(lw+ih+wh)

We have l = 5.5, w = 5 and h = 13. Substitute:

S.A.=2(5.5\cdot5+5.5\cdot13+5\cdot13)\\\\S.A.=2(27.5+71.5+65)\\\\S.A.=2(164)\\\\S.A.=328

SCORPION-xisa [38]2 years ago
7 0
5.5 • 5= 27.5+27.5+65+65+71.5+71.5=328

13•5=65
13•5.5=71.5

THE ANSWER IS 328
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Step-by-step explanation:

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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

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Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

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For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

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The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

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Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

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Step-by-step explanation:

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