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3 years ago

Let f(x) = x + 7 and g(x) = x − 4. Find f(x) ⋅ g(x). (1 point) x2 − 3x −28 x2 − 3x − 11 x2 + 3x − 28 x2 + 3x − 11

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

$f(x)=x+7\\g(x)=x-4\\f(x)*g(x)=(x+7)(x-4)\\f(x)*g(x)=x^2+3x-28$

So it's x^2+3x-28

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I think you could multiply or divide. Hope this helps:)

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3 years ago

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katrin2010 [14]

Answer:

5 5/6 + 55x/24

Step-by-step explanation:

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3 years ago

Do I need to put parentheses in this? Why it why not?

Oksana_A [137]

Answer:

Parentheses can change the result of the answer. If you want to add 4 and 0.95 first, then multiply that number by 3, then you need parentheses.

Step-by-step explanation:

When you are given the question 3 X 4 + 0.95, it has to types of operations. <u>People solve using the order PEDMAS</u>:

Parentheses,

Exponents,

Division and Multiplication,

Addition and Subtraction.

Since there are <u>no parentheses</u> or exponents, the solver will do multiplication first, then addition.

3 X 4 + 0.95 Multiply first

= 12 + 0.95 Now add

= 12.95 Answer without parentheses

If you add <u>parentheses around 4 + 0.95</u>, the answer would change. According to PEDMAS, the parentheses must be solved before anything else.

3 X (4 + 0.95) Add inside parentheses

= 3 X (4.95) Now multiply

= 14.85 Answer with parentheses

If you added <u>parentheses around 3 X 4</u>, the answer would not change, because you still multiply first.

(3 X 4) + 0.95 Solving parentheses first

= 12 + 0.95 Add

= 12.95 Answer same as original

3 0

2 years ago

Solve each equation 6=3x-5+8x

Shalnov [3]

6 = 11x-5
11x=11
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4 0

3 years ago

If possible help me in this. I need to find the two odd numbers...

Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer: x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\$

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15 or -15, -13</h3>

4 0

2 years ago