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Irina-Kira [14]
3 years ago
6

Need help on this one too ​

Mathematics
1 answer:
KiRa [710]3 years ago
4 0

I think it's none because that should be communitive and that's not there so.

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What is the perimeter of rectangle with the sides 8cmand 12cm
erik [133]

Answer:

The correct answer is 40 cm.

6 0
3 years ago
Read 2 more answers
Help ngnfkxkdkmdfmkdkfkfmmfkfkdjx​
nadya68 [22]

9514 1404 393

Answer:

  A: 8x +24

  B: not equivalent for any value of x

Step-by-step explanation:

<u>Part A</u>:

The factor of 4 on the outside of parentheses multiplies each term inside:

  M = 4(2x) +4(6)

  M = 8x +24 . . . . . expression equivalent to M

__

<u>Part B</u>:

Expressions M and N are not equivalent for any value of x. They are equivalent if their difference is zero or can be made to be zero. Subtracting N from M, we find the difference to be ...

  M -N = (8x +24) -(8x +10) = 14

There is no value of x that will make the difference of 14 become zero.

5 0
3 years ago
F(x)=x/3-2 g(x)=3x^2+2x-6 (f+g)(x)
Romashka [77]

Answer:

Hope it helps bhhhhbbbbbbhb

8 0
3 years ago
A car sells for $20,930. If the rate of depreciation is 6%, what is the value of the car after 8 years? Round to the nearest tho
Verizon [17]

Answer: 10,883.6

Step-by-step explanation: So first we have to find out what the depreciation is and to find that we have to take the 20,930 and times it by 0.06 (6%) which is 1,255.8,

So, we then times 1,255.8 by 8 because 8 years of depreciation, which is 10,046.4,

Finally we take 20,930 (the cars total value) and subtract the depreciation from it (10,046.4) so in 8 years the car is worth 10,883.6

If you need any further instruction or help let me know!‬

5 0
4 years ago
What is $2.99 plus 7%??? please help me
PtichkaEL [24]
7% of 2.99 is 2.99 ÷ 100, then multiplied by 7. 2.99 divided by 100 is 0.0299. 0.0299 is 1% of 2.99. Then multiply that (0.0299) by 7 to get 7%; 7% = $0.21. Then add that to $2.99 and you get $3.20.

Please mark as brainliest if this answer help you. I hope it did!
8 0
3 years ago
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