Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .
Answer:
A cuz x+6 is double x-3 so divide them and equate it to 2 you'd get x+6 = 2x-6
12=2x-x
30b + 100u = 900
5b + 25u = 200....multiply by -6
------------------
30b + 100u = 900
-30b - 150u = - 1200 (result of multiplying by -6)
------------------add
-50u = - 300
u = 6 <== upgrated phones sold
30b + 100u = 900
30b + 100(6) = 900
30b + 600 = 900
30b = 900 - 600
30b = 300
b = 10 <== basic phones sold
8.57 for the first one and, I’m not sure a bout the second time though
300 pennies multiply 6×50=300
