3 years ago

If f(x) = 2 + x and g(x) = 3 - x, what is go f(-1)?

Mathematics

1 answer:

gavmur [86]3 years ago

3 0

Answer:

g(f(-1)) = 2

Step-by-step explanation:

f(x) = 2 + x

g(x) = 3 - x

if you need to find g(f(-1)); find f(-1) first

f(-1) = 2 + (-1) = 1

f(-1) =1; now plug this into g(1)

g(1) = 3 - 1 = 2

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If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

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Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$