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SashulF [63]
3 years ago
5

If f(x) = 2 + x and g(x) = 3 - x, what is go f(-1)?

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

g(f(-1)) = 2

Step-by-step explanation:

f(x) = 2 + x

g(x) = 3 - x

if you need to find g(f(-1)); find f(-1) first

f(-1) = 2 + (-1) = 1

f(-1) =1; now plug this into g(1)

g(1) = 3 - 1 = 2

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If the slope of PQ is 2/3 and the slope of QR is-1/2 , find the slope of SR so that PQRS is a parallelogram.
schepotkina [342]
SR is parallel to PQ so has the same slope as PQ, which is 2/3
6 0
3 years ago
Answer the question below please
DaniilM [7]

The correct answer is : of those planning to not to go on vacation, more of them are women.

The correct answer is (C)

<h3>What is probability?</h3>

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event

Given:  total people asked =145

The first option is not correct because plan to go on vacation women are more than men.

The second option is also incorrect because more women were asked than men.

The third option is correct because out of planning who were not going any vacation, women are more than of men.

The fourth option is incorrect because More men plan to go on vacation.

Learn more about probability here:

brainly.com/question/11234923

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5 0
1 year ago
Write an equation in point-slope form of a line with a slope of –4 that goes through the point J(–5, 6).
Fittoniya [83]
The equation is y = -4x + 26.
5 0
3 years ago
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
D) A shopkeeper bought two radios for Rs 6,000. He sold one of them at a profit of 20℅
Orlov [11]

Answer:

2400 and 3600

Step-by-step explanation:

Radio 1 cost = x

Radio 2 cost= 6000- x

  • x*1.2+(6000-x)*0.9= 6000*1.02
  • 1.2x-0.9x+5400=6120
  • 0.3x= 6120-5400
  • 0.3x= 720
  • x=720/0.3
  • x= 2400
  • 6000- x= 3600
8 0
3 years ago
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