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densk [106]
3 years ago
6

b) The volume of a cuboid is 200 m². Its length and height are 10 m and 5 m respectively. Need it fast

Mathematics
1 answer:
Ratling [72]3 years ago
6 0
Bad question. Volume is cubic units, not square units.
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If someone could get both it would be greatly appreciated
Irina-Kira [14]
The answer to your question is 8.6
7 0
3 years ago
Read 2 more answers
The volume, V, of a cone is calculated using the formula V 1 Tr?h, where r is the radius of the base and h 3 is the height of th
e-lub [12.9K]

Answer

r = 20.25

this is the awnser i know im only in 6th grade but im good at math

8 0
3 years ago
Explain how you determine an equation for a line using a table of input/output values.
Lubov Fominskaja [6]
Example :

            x               y
            1               3
            2               6
            3               9
            4               12

first thing u do is pick any 2 points (x,y) from ur table

(1,3) and (2,6)
now we sub those into the slope formula (y2 - y1) / (x2 - x1) to find the slope
(y2 - y1) / (x2 - x1)
(1,3)....x1 = 1 and y1 = 3
(2,6)...x2 = 2 and y2 = 6
sub
slope = (6 - 3) / (2 - 1) = 3/1 = 3

now we use slope intercept formula y = mx + b
y = mx + b
slope(m) = 3
use any point off ur table...(1,3)...x = 1 and y = 3
now we sub and find b, the y int
3 = 3(1) + b
3 = 3 + b
3 - 3 = b
0 = b

so ur equation is : y = 3x + 0....which can be written as y = 3x...and if u sub any of ur points into this equation, they should make the equation true....if they dont, then it is not correct

and if u need it in standard form..
y = 3x
-3x + y = 0
3x - y = 0 ...this is standard form
6 0
3 years ago
The graph of a linear function passes through the points (2, 4) and (8, 10).
Keith_Richards [23]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ 8}}\quad ,&{{ 10}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{10-4}{8-2}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=2\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}
8 0
3 years ago
Which of the following is equivalent to the midpoint between the points (8, -9) and (0, 5)?
olya-2409 [2.1K]
Add up the x points and divided by 2
same to go for the y points
so the and is (4,-2)

7 0
3 years ago
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