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arlik [135]
3 years ago
14

I’m so confused please help , this is 100 points

Mathematics
2 answers:
sesenic [268]3 years ago
6 0

Answer:

m`1 = 43` 2,3

   m<2 1/12*  

 and m <3 = 1,3/2

Step-by-step explanation:

Anna11 [10]3 years ago
3 0

Answer:

m1= 47 degrees

m2= 137 degrees

m3= 31 degrees

Step-by-step explanation:

90+43=133

180-133=47

<u><em>47 degrees</em></u>

180-43=137

<u><em>137 degrees</em></u>

137+12=149

180-149=31

<u><em>31 degrees</em></u>

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A cone and its dimensions are shown in the diagram above.
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Answer:

The answer closest is answer D) 62.13

Step-by-step explanation:

I think u multiply them.

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Kayla hikes 25 meters in 13.7 seconds. Which of the following closest to how far she will hike in 6 minutes, if she maintains th
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<u>Answer:</u>

197.28 meters in 6 minutes

<u>Step-by-step explanation:</u>

13.7 seconds ÷ 25 meters = 0.548 meters in 1 second

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0.548 meters in 1 second x 360 seconds = 197.28 meters in 6 minutes

<em>Hopefully this helped! Sorry if wrong. You are loved and you are beautiful/handsome!</em>

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7 0
3 years ago
Each month, Liz pays $35 to her phone company just to use the phone. Each text she sends costs her an additional $0.05. In March
Firdavs [7]
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3 0
3 years ago
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melisa1 [442]
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8 0
4 years ago
Read 2 more answers
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
4 years ago
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