Answer:
Step-by-step explanation:
If we take out the extra $3, we can group the bills into one each of $5 and $1, for a value of $6. There will be 7 such groups in the remaining $42.
That means there are 7 bills of the $5 denomination, and 3 more than that (10 bills) of the $1 denomination.
There are 7 $5 bills and 10 $1 bills.
_____
If you want to write an equation, it is usually best to let a variable stand for the most-valuable contributor. Here, we can let x represent then number of $5 bills. Then the value of the cash box is ...
5x +(x+3) = 45
6x = 42 . . . . . . . . subtract 3, collect terms
x = 7 . . . . . . . . . . . there are 7 $5 bills
x+3 = 10 . . . . . . . . there are 10 $1 bills
You may notice that this working parallels the verbal description above. (After we subtract $3, x is the number of $6 groups.)
135 divided by 18 is 7.5 so I would guess 7 each week and maybe possibly 8 on some weeks
Answer:
The solution is given below:
Step-by-step explanation:
The computation is shown below:
= 19 + 7 divided by 2 - 5
= (19 + 7) ÷ (2) - 5
= 26 ÷ 2 - 5
= 13 - 5
= 8
Hence, after solving this the value would be 8
Therefore it is equal to the 8
Hence, the given statement is true
Answer: The average velocity of the object over the time interval [3,6] is 20.
Step-by-step explanation:
Since we have given that
s(3) = 156
s(6) = 216
We need to find the average velocity over the time interval [3,6].
So, average velocity becomes
Hence, the average velocity of the object over the time interval [3,6] is 20.
It would be D. because the volume of a sphere is 4/2 x pi x radius^3.
