Answer:
![\textbf{$x \in (-\infty, 3] $}\\](https://tex.z-dn.net/?f=%5Ctextbf%7B%24x%20%5Cin%20%28-%5Cinfty%2C%203%5D%20%24%7D%5C%5C)
Step-by-step explanation:
![\textup{Given:}\\$ 4x + 6 $\textup{Subtracting $6$ from both the sides }\\$ 4x \leq 18 - 6 \hspace{5mm} (=12) $\\\textup{Dividing by $4$ on both the sides: \hspace{15mm} [Note that the sign of the inequality changes only when we divide it by a negative number]}\\$$ x \leq 3 $$\\\textup{$x$ can be any real number less than or equal to 3.}\\$ \iff x \in R^- \cup \{a : 0 \leq a \leq 3\} $](https://tex.z-dn.net/?f=%5Ctextup%7BGiven%3A%7D%5C%5C%24%204x%20%2B%206%20%24%5Ctextup%7BSubtracting%20%246%24%20from%20both%20the%20sides%20%7D%5C%5C%24%204x%20%5Cleq%2018%20-%206%20%5Chspace%7B5mm%7D%20%28%3D12%29%20%24%5C%5C%5Ctextup%7BDividing%20by%20%244%24%20on%20both%20the%20sides%3A%20%5Chspace%7B15mm%7D%20%5BNote%20that%20the%20sign%20of%20the%20inequality%20changes%20only%20when%20we%20divide%20it%20by%20a%20negative%20number%5D%7D%5C%5C%24%24%20x%20%5Cleq%203%20%24%24%5C%5C%5Ctextup%7B%24x%24%20can%20be%20any%20real%20number%20less%20than%20or%20equal%20to%203.%7D%5C%5C%24%20%5Ciff%20x%20%5Cin%20R%5E-%20%5Ccup%20%5C%7Ba%20%3A%200%20%5Cleq%20a%20%5Cleq%203%5C%7D%20%24)
Answer by JKismyhusbandbae: So this is really simple. You are probably making this out harder than it needs to be. Consider the set of ordered pairs {(-1,0), (4,-5), (6,-6), (9,11), (10,14)}. This set of ordered pairs is a function because for each value of x there is one and only one y-value. This means that the x value never repeats. Therefore any function is a function when the x value never repeats.
Looking at the table we want to find all it's ordered pairs: (0,4), (1,2), (2,3), (3,9), (4,1).
F(2) is 3 so when x equals 2.
So the ordered pair is (2,3) 2 is the x value and the f(2) is 3.
Answer:
4xy
Step-by-step explanation:
2 x 2 = 4, then just plop the x and y down, and there's your answer
D 110, gimme that young brainlyest
