The Answer Is -54xy(9xy-2y^4+10x)
Answer:
Zeros are x = −2, −3 .
Step-by-step explanation:
Given : f(x) = x² + 5x + 6.
To find : What are the zeroes of f(x).
Solution : We have given that
f(x) = x² + 5x + 6.
To find the zeros of the function we need to set f(x) = 0.
x² + 5x + 6 = 0.
On factoring
x² + 3x +2x + 6 = 0.
Taking common x from first two term and 2 from last two terms
x ( x + 3) +2 ( x +3) = 0.
On grouping
(x + 3) (x + 2) = 0
Now, x + 3 = 0 and x + 2 = 0
x = -3 and x = -2
Therefore, Zeros are x = −2, −3 .
Answer:
Hope this helps out dude!
Step-by-step explanation:
Answer:
3y^2 - (y + 2) (y - 2) = 0
<=> 3y^2 - (y^2 - 4) = 0
<=> 2y^2 + 4 =0
<=>y^2 + 2 = 0
=> Because y^2 is always equal or larger than 0, there is no real solution.
Hope this helps!
:)
