Answer:
The total earned money over the 5 year period=$14,000
Step-by-step explanation:
We are given that
Principle amount, P=$10000
Rate of interest, r=8%
Time, t=5 years
We have to find the total earned money over the 5 year period.
We know that
Simple interest=
Using the formula
S.I=[tex]\frac{10000\times 8\times 5}{100}{/tex]
S.I=$4000
Now,
Amount=P+S.I
Amount=10000+4000
Amount=$14000
Hence, the total earned money over the 5 year period=$14000
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Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
I think it is $0.27 because 15% of 1.80 is 0.27
Answer:
C= 10.6
Step-by-step explanation:
AB^2=AC^2+CB^2
C^2=7^2+8^2
C^2= 113
√113=10.630
