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Masja [62]
3 years ago
12

Based on this equation, estimate the score for a student that spent 3.83.83, point, 8 hours studying.

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

0.48

hope that help!!!

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Can u guys PLEASE answer this question ASAP.
Anastasy [175]

Answer:

93.75 Kg

Step-by-step explanation:

Farmer spreads 25 kg fertilizer over an area of 4000 m square .

So, Over 1 m square , \frac{25}{4000} kg of fertilizer will be needed

As we know , 1 hectare = 10,000 m square.

So, 1.5 hectare equals 15,000 m square.

So, for 15,000 m square , Fertilizer needed will be equal to                                      \frac{25}{4000} ×15,000 = 93.75 Kg

So, 93.75 Kg of fertilizer is needed for 1.5 ha of land.

                                     

4 0
3 years ago
Find the percent increase from 200 to 240
vlabodo [156]

Answer:

  20%

Step-by-step explanation:

The percentage change can be found from ...

  % change = ((new value)/(reference value) -1) × 100%

  = (240/200 -1) × 100%

  = 0.20 × 100%

  = 20%

240 is an increase of 20% from 200.

3 0
3 years ago
What are the first 12 multiples of 4
Mariulka [41]
4,8,12,16,20,24,28,32,36,40,44,48
6 0
4 years ago
Read 2 more answers
According to a bridal magazine, the average cost of a wedding reception for an American wedding is $8213. Assume that this avera
Thepotemich [5.8K]

Answer:

a. The point estimate of the corresponding population mean is of $8213.

b. The margin of error is of $103.

c. The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. What is the point estimate of the corresponding population mean?

The sample mean is of $8213. So, by the Central Limit Theorem, the point estimate of the corresponding population mean is of $8213.

b. What is the margin of error for this estimate (use2 standard deviations (divided by Vn) to either side of the mean is used when no specific confidence level is stated).

Sample of 450, standard deviation of $2185. So

M = \frac{2185}{\sqrt{450}} = 103

The margin of error is of $103.

c. Create and interpret a 98% confidence interval for the corresponding population mean.

The confidence interval is given by:

\mu \pm M*z

In which \mu is the sample mean and z is the value related to the confidence level.

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.325.

Then

\mu - M*z = 8213 - 2.325*103 = 7973.5

\mu + M*z = 8213 + 2.325*103 = 8452.5

The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

4 0
3 years ago
If t(n) =5-2n what is the 4th term
Nuetrik [128]
I think im not completely sure but it might be -3
5 0
4 years ago
Read 2 more answers
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