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wariber [46]
3 years ago
12

An Air Conditioner uses 850 Watts of electricity and local emissions from electricity produce 1.37 pounds of CO2 per kWh. If you

open a window instead of using the AC for 6 hours, how many pounds of CO2 would you keep from entering the atmosphere?
Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer: 6,987,000 pounds fo CO₂ per kWh.

Step-by-step explanation: <u>Quilowatt</u>-<u>hour</u> <u>(kWh)</u> is a unit of energy that measures the amount of energy expended in 1 hour.

The AC uses 850 Watts, which in kW is 850,000 kW

If you leave the AC on for 6 hours, it will consume

850,000(6) = 5,100,000 kWh

Eletricity produces 1.37 pounds of CO₂ per kWh, then in 5,100,000 kWh:

1.37 \frac{pounds}{kWh}.(5,100,000kWh) = 6,987,000 pounds

If you open a window for 6 hours, you would keep 6,987,000 pounds of CO₂ for entering the atmosphere.

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3.
sergey [27]

Answer:

His money earned $36 after 3 months

Step-by-step explanation:

* Lets revise the rules of simple interest

- Simple Interest Equation (Principal + Interest)

 A = P(1 + rt)

- Where:

• A = Total amount (principal + interest)  future amount

• P = Principal Amount

• I = Interest Amount

• r = Rate of Interest per year in decimal; r = R/100

• t = Time Period involved  

* To calculate the interest I use the formula

  I = P × r × t

* Lets solve the problem

- The rate is annual

- The interest calculated after 3 months

∴ I = P × R/100 × t/12

∵ P = $3600.00

∵ R = 4%

∵ t = 3 month

∴ I = 3600.00 × 4/100 × 3/12 = $36

* His money earned $36 after 3 months

5 0
3 years ago
Simplify.<br><br> 8r(4 - p)<br><br> 32r -p<br> 32r - 8rp<br> 32 - rp<br> 4 - 8rp
gizmo_the_mogwai [7]

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<em>hope </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

4 0
3 years ago
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The annual 2-mile fun-run is a traditional fund-raising event to support local arts and sciences activities. It is known that th
victus00 [196]

Answer: 0.0228

Step-by-step explanation:

Given : The  mean and the standard deviation of finish times (in minutes) for this event are respectively as :-

\mu=30\\\\\sigma=5.5

If the distribution of finish times is approximately bell-shaped and symmetric, then it must be normally distributed.

Let X be the random variable that represents the finish times for this event.

z score : z=\dfrac{x-\mu}{\sigma}

z=\dfrac{19-30}{5.5}=-2

Now, the probability of runners who finish in under 19 minutes by using standard normal distribution table :-

P(X

Hence, the approximate proportion of runners who finish in under 19 minutes = 0.0228

8 0
3 years ago
Find the LCD (least common denominator) of the pair of fractions. Do not combine the fractions; only find the LCD.
Alla [95]
12

4x3=12 and 6x2=12
8 0
3 years ago
What is the volume of the figure below, which is composed of two cubes with side lengths of 7 units?
wariber [46]

Answer:

B) 686 cubic units

Step-by-step explanation:

If one cube has a side length of 7, then it equals to 343 cubic units. Since there are 2 cubes, this translates to 686 cubic units.

6 0
2 years ago
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