4. Timothy deposited $3500 into an accountthat pays 4.3% simple interest and keeps it

Mathematics

1 answer:

hjlf2 years ago

6 0

$3,500(4.3%)4= $602

His new account balance after interest is $602

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When the following expression is written in simplest form, what is the coefficient of the variable term? -2.5y + 8y - 10.5y

LUCKY_DIMON [66]

Answer:

Option 1 is correct.

-5

Step-by-step explanation:

Given:

The given expression is.

$=-2.5y+8y-10.5y$

Write the given expression in simplest form.

$=-2.5y+8y-10.5y$

Add negative term of y.

$=-13y+8y$

$=-5y$

The simplest form of given expression is $=-5y$

Therefore, the coefficient of the variable term is -5

7 0

3 years ago

3/10 divided by -3 1/2

Nitella [24]

The answer to this question is -3/35

3 0

3 years ago

What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .