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svetlana [45]
3 years ago
13

Crystal has three packages of drink mix and two bottles of lemonade each package makes 64 oz of lemonade each bottle contains 48

oz how many 6 oz glasses of lemonade can she serve​
Mathematics
1 answer:
irakobra [83]3 years ago
6 0

Number of glass can serve is 48 glass

<u>Given:</u>

Number of drink mix package = 3

Quantity of each package = 64 oz

Number of lemonade bottle = 4

Quantity of each lemonade bottle = 48 oz

Quantity of each glass = 6 oz

<u>Find:</u>

Number of glass can serve

<u>Computation:</u>

Total quantity of mix drink = 3 × 64

Total quantity of mix drink = 192 oz

Total quantity of lemonade = 2 × 48

Total quantity of mix drink = 96 oz

Total drink = 192 + 96

Total drink = 288 oz

Number of glass can serve = Total drink / Quantity of each glass

Number of glass can serve = 288 / 6

Number of glass can serve = 48 glass

Learn more:

brainly.com/question/21348767?referrer=searchResults

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6)

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43-34 = 9; 52-43 = 9; 61-52 = 9

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 34

difference:  d = 9

so the formula:

                         a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}

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difference:  d = -4

so the formula:

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difference:  d = -7

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The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 7

difference:  d = 1.5

so the formula:

                         a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}

10)

30, 22¹/₂, 15, 7¹/₂, ...

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The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 30

difference:  d = -7¹/₂

so the formula:

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It also means that the corresponding angles are necessarily equal.

BD = 2

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ED = 3.61

BA = 2 × BD = 2 × 2 = 4

BC = 2 × BE = 2 × 3 = 6

CA = 2 × ED = 2 × 3.61 = 7.22

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Adj = Adjacent side = BE = 3

Hyp = hypotenuse side = ED = 3.61

Cos ∠D = (3/3.61)

Cos ∠A can also be similarly obtained from trigonometric relations as (adj/hyp)

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