Answer is: <span>the temperature of the reaction is 546</span>°C.
k₁ = 1,1·10⁻⁴ 1/s.
T₁ = 470 °C = 743,15 K.
Ea = 264 kJ/mol = 264000 J/mol.
k₂ = 4,36·10⁻³ 1/s.
R = 8,314 J/K·mol.
T₂ = ?
Natural logarithm<span> of Arrhenius' equation:
</span>lnk₁ = lnA - Ea/RT₁.
lnk₂ = lnA - Ea/RT₂.
ln(k₂/k₁) = (Ea/R) · (1/T₁ - 1/T₂).
ln( 4,36·10⁻³ 1/s / 1,1·10⁻⁴ 1/s) = (264000J/mol ÷ 8,314 J/K·mol) · ·(1/743,15K - 1/T₂).
3,68 = 31753,66 K · (0,00134 1/K - 1/T₂).
3,68 = 42,728 - 31753,66 · (1/T₂).
1/T₂ = 0,00122.
T₂ = 819 K = 546 °C.
Sulfur I suck at chemistry but this is what my sister says
Answer:
A options hydrogen
Explanation:
valence outermost element is hydrogen.