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777dan777 [17]
3 years ago
11

A 0.229-g sample of an unknown monoprotic acid is titrated with 0.112 m naoh. the resulting titration curve is shown here. part

a determine the molar mass of the acid. express your answer using two significant figures.
Chemistry
1 answer:
Kazeer [188]3 years ago
4 0
It would be 0.341 because if you add 0.229 and 0.112 it will be 0.341
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What volume of air is needed to burn completely 100cm of propane?
Evgesh-ka [11]

Answer:

See below

Explanation:

propane mole weight = 44 gm / mole

100 gm / 44 gm / mole = 2.27 moles

From the equation, 5 times as many moles of OXYGEN (O2)are required

   = 11.36 moles of oxygen

           at <u>STP</u> this is 254.55  liters of O2 (because 22.4 L = one mole) and

Using oxygen as 21 percent of air means that

      .21 x = 254.55 =       x = <u>1212.12 liters of air required </u>

5 0
2 years ago
Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
How does adding an atom affect the position of existing atoms or lone pairs?
Paha777 [63]

Adding an atom will increase the repulsion between existing atoms and lone pairs. Added atom will result in bond pair-bond pair and bond pair-lone pair repulsion. The magnitude of the lone pair-bond pair repulsion is greater than the bond pair-bond pair repulsion. The added atom will change the electron geometry and bring about a distortion in the molecular geometry.

8 0
3 years ago
Read 2 more answers
In stomach, Hydrochloric acid kills micro-organisms in the food. Stomach juices begin to break down p to amino acids. Stomach ju
Butoxors [25]

\huge{ \underline{ \boxed{ \bf{ \green{Answer:}}}}}

Inside the stomach, Hydrochloric acid kills micro-organisms in the food. Stomach juices begin to break down <u>proteins</u> to amino acids.

✤ So, Fill the blank with proteins.

<h3><u>Explanation:-</u></h3>
  • Inside the stomach, the digestion of proteins starts due to the action of pepsin enzyme.
  • But this enzyme remains inactive and is activated by the Hydrochloric acid(HCl).
  • The Hydrochloric acid also helps in killing the germs and microbes which entered along with food.
  • The mucous lines the wall of stomach to protect it from the harm caused by HCl because HCl is a strong acid.
  • In stomach, The partial digestion of proteins occur and rest is digested in the small intestine by Trypsin(Pancreatic enzyme) and Intestinal juices.

<u>━━━━━━━━━━━━━━━━━━━━</u>

6 0
3 years ago
A solution of silver chlorate reacts with a solution of lithium iodide.
Anettt [7]

Answer: Ag^+(aq)+I^-(aq)\rightarrow AgI(s)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)

The complete ionic equation is:

Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.

Thus the net ionic equation is:

Ag^+(aq)+I^-(aq)\rightarrow AgI(s)

7 0
3 years ago
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