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7nadin3 [17]
3 years ago
13

HURRRYYYYYYYYYYYYYYYYYYYY PLZZZZZZZZZz ALL OF EM

Mathematics
1 answer:
eduard3 years ago
3 0

Answer:

25000x10^5=2500000000

Step-by-step explanation:

so a

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A group of students where asked about the number of e-mails they each send that day. The results are: 0, 1, 1, 2, 3, 3, 4, 4, 6,
valkas [14]

Answer:

Choice D

Step-by-step explanation:

After writing the data down seperate the values according to the x-axis on the graphs. You will find that 6 people chose between 0 to 3, 4 people chose between 4 to 7, 3 people chose between 8 to 11 and 2 people chose between 12 to 15.

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kifflom [539]

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10+20x-12

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2 years ago
What plus 4/3 equals 19/3 in the simplest form?
dangina [55]
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3 years ago
Can someone help please!
sammy [17]

Answer: 8 units^2

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Find the sum of all positive integers less than 200 that are divisible by 7.
Troyanec [42]

Step-by-step explanation:

the positive integer numbers that are divisible by 7 are an arithmetic sequence by always adding 7 :

a1 = 7

a2 = a1 + 7 = 7+7 = 14

a3 = a2 + 7 = a1 + 7 + 7 = 7 + 2×7 = 21

...

an = a1 + (n-1)×7 = 7 + (n-1)×7 = n×7

the sum of an arithmetic sequence is

n/2 × (2a1 + (n - 1)×d)

with a1 being the first term (in our case 7).

d being the common difference from term to term (in our case 7).

how many terms (what is n) do we need to add ?

we need to find n, where the sequence reaches 200.

200 = n×7

n = 200/7 = 28.57142857...

so, with n = 29 we would get a number higher than 200.

so, n=28 gives us the last number divisible by 7 that is smaller than 200 (28×7 = 196).

the sum of all positive integers below 200 that are divisible by 7 is then

28/2 × (2×7 + 27×7) = 14 × 29×7 = 2,842

6 0
2 years ago
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