Answer:
The total charge in an atom is zero or it is neutrally charge. both nulify each others charge.
- If the atom has some charge in it then it is called an ion.
Answer:
its corresponding angles postulate
Step-by-step explanation:
<span>Use the Pythagorean Theorem to solve. This will be a right triangle:
=
Let the slope = the hypotenuse = c
Let one side = a=8
Let the other side =b =15
Plug-in the values and solve for the c-term
Check you answer by plugging the value of "c" back into the orignial equation and solve.
.
=
=
=
=
=
17=c
.
Check by plugging into the original equation and solve.
=
=
289=289 [checks out]</span>
<span>it must be nnnnnnnnnnnnnnnnnnnnnnnnn
4.37%
</span>
Answer:
Step-by-step explanation:
2005 AMC 8 Problems/Problem 20
Problem
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?
$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$
Solution
Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.
See Also
2005 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 19 Followed by
Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
