A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.
Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.
Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.
Answer:
12
Step-by-step explanation:
1/12x1/x
1x=12x1
x=12
11 square. units × 7 square. units × 1/2= B. 38.5 square. units.
Answer:
first one: 8
second one: 3
Step-by-step explanation:
-3x + y = -24 |÷(-3x)
y = 8
y = 7x + 22 |-y
(y would be 1; the 7x moves to the other side.) meams:
7x = 21 |÷7
x = 3
