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Kobotan [32]
3 years ago
9

1. Ivan bought three magazines for $6.50 each. The sales tax was 7%. What

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

I got 6.955

I would round and say he paid $6.96

Step-by-step explanation:

i multiplied 6.50 by 1.07

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What is the product of -2/7 and -3/6
Andrew [12]

Hey!

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Product means multiplication.

-2/7 * -3/6 = -6/42 = -1/7

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Hence, the answer is \Large\boxed{\mathsf{-1/7}}

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Hope This Helped! Good Luck!

6 0
2 years ago
Please Help!!!!! I need the answer for my quiz!!!!
kondaur [170]

Answer:

I think its 3 1/4

Step-by-step explanation:

9 3/4 ÷ 3 = 3 1/4

Srry if im wrong

3 0
3 years ago
Read 2 more answers
CALCULATE (5-3)^2 AND DEDUCE √14-6√5​
weeeeeb [17]
(5-3)^2 is = -4 , the second one is -9.67
4 0
2 years ago
WHY must the same operation be performed on both sides of an equation? ​
lys-0071 [83]

Answer:When you are given a problem, the two sides are equal, so they are equally weighted. As long as you do the same thing on both sides, they remain the same weight. The only way that one side can become "more weight" on a side is if you make a math mistake, and thus the answer would not satisfy the original equation

Step-by-step explanation:looked it up... have a good day!

8 0
3 years ago
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
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