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miskamm [114]
3 years ago
5

T = 4k + 9

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0
A ) 17 because 4*2+9=8+9=17
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A container has peppermint gum and spearmint gum. There are 40 pieces of peppermint gum in the container and the ratio of pepper
Anit [1.1K]

Answer:

16 pieces of spearmint gum

Step-by-step explanation:

For every five pieces of peppermint gum, there are 2 pieces of spearmint gum.

First, divide the total number of peppermint gum by 5:

40/5 = 8

Multiply this number by 2 (pieces of spearmint) to get the number of spearmint gum pieces:

8 x 2 = 16

Proof:

Ratio is 40 : 16, dividing this by 8 will reduce the ratio to 5:2

7 0
3 years ago
Describe the pattern in the sequence. Find the next two terms of the difference -2, -5,-8, -11
PSYCHO15rus [73]

Hello from MrBillDoesMath!

Answer:

"-3" is added to a sequence member to get the next number. This next two terms are -14 and  -17


Discussion:

Note that -2 -3 = -5 and

                -5 -3 = -8 and

                -8 - 3 = -11


"-3" is added to a sequence member to get the next number. This implies that the next two terms are -11 -3 = -14 and -14 -3 = -17

Regards,  

MrB


5 0
3 years ago
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
Help me solve for z, step by step if you can
zheka24 [161]

Answer:

z=6

Step-by-step explanation:

z/3 + 1/2 = 5/2

Subtract 1/2 from each side

z/3 + 1/2-1/2 = 5/2-1/2

z/3 = 4/2

z/3 =2

Multiply each side by 3

z/3*3 = 2*3

z = 6


5 0
3 years ago
2(3r+7)−(2+r)<br> I need the answer
dimaraw [331]

Answer:

5r+12

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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