R+4.6+9=3r-11.7-7r
combine all like terms on one side of the equal sign
r+4.6-4.6+9=3r-11.7-7r-4.6
r+9-9=3r-11.7-7r-4.6-9
r-3r=3r-3r-11.7-7r-4.6-9
r-3r+7r=-11.7-4.6-9-7r+7r
r-3r+7r=-11.7-4.6-9
add them all into one term on each:
5r=-25.3
divide by 5 on both sides:
r= -5.06
Anybody know? I need this
Answer: The answer is 
Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.
Let, AC = 3x and CM = 4x.
In the right-angled triangle ACM, we have
Now,
Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.
So,
Comparing equations (A) and (B), we have
Thus,
Answer:
m<PRQ=15°
Step-by-step explanation:
so we're given that PQ and RQ are sides of a regular 12-sided polygon (dodecagon)
a regular polygon is a polygon that has all angles be the same measure AND have all sides be the same length
because of that, PQ=RQ, and ΔPQR is isoceles
now we need to find what the question is asking for: m<PRQ
because of base-angles theorem, m<PRQ=m<RPQ
we need to find m<PQR
a dodecagon is 1800° in measure
and we need 1/12th of that measure, since <PQR is 1 out of the 12 interior angles on the dodecagon (a dodecagon has 12 vertecies, so 12 angles). Also because the polygon is regular, every interior angle has the same measure.
so find the measure of <PQR
<PQR= 1/12*1800=150°
now to find the measure of <PRQ:
there are 180° in a triangle
so subtract 150° from 180°
180°-150°=30°
30° is the sum of the base angles (<PRQ is one of the base angles in a triangle)
the base angles are the same measure, so that means the measure of <PRQ is 1/2 the measure of the sum of the base angles
therefore m<PRQ=15°
hope this helps!
Answer: Solution
Step-by-step explanation: I believe the answer is solution
