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kolbaska11 [484]
3 years ago
9

What is the correct answer?

Mathematics
1 answer:
lora16 [44]3 years ago
4 0

Answer:

B: y= 1/4x - 2

Step-by-step explanation:

hope this help you

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No explanation needed just the answer please
Otrada [13]

Answer:

53

Step-by-step explanation:

65x- 12  = 43x + 10

65x - 43x = 10 + 12

22x = 22

x = 22/22

<u>x = 1 </u>

(65x- 12) =

65 * 1 - 12 =<u> 53</u>

43x + 10

43 * 1 -12 = <u>53</u>

5 0
3 years ago
F(x)
mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if \lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x). This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty

\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}

g(x) = \frac{1}{x + 1}

The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0
2 years ago
The perimeter of a rectangle is 48 ft. If the length is thrice its width, find the dimensions of the rectangle.
VikaD [51]

Answer:

here you go

Step-by-step explanation:

8 0
3 years ago
Factorise <br> 5x - 15.<br> could you please show working out.<br> Thanks
Gennadij [26K]
5(x -3) is the answer
7 0
3 years ago
(y-8)(y-8)(y-8)<br><br> How do I multiply OR find the special product of this problem ?
photoshop1234 [79]

Answer:

2x^3-23y^2+72-128

Step-by-step explanation:

its like when you just do two

do the first 2 first

(y-8)(y-8)

this is (y^2 -8y+y^2+16) simplify (2x^2-7y+16)

then add the other bracket

(2x^2-7y+16) (y-8)

2x^3-16x^2-7y^2+56y+16y-128 simplify

5 0
3 years ago
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