You ca also use sss, sas, asa, aas, and that, hl.
Answer:
the answer would be D40 because if you have 15 you take and you subtract the six from it and you wouldn't get 0.6 or 0.4 so those to A&B or eliminated but C & D where would be the only two would left and it would be D because 6 and 9 or almost equal to each other so it would be. 40 which sould be D
1.
is the area under the curve to the left of
, which is a trapezoid with "bases" of length 2 and 5 and "height" 0.2, so
![P(X](https://tex.z-dn.net/?f=P%28X%3C5%29%3D%5Cdfrac%7B5%2B2%7D2%5Ccdot0.2%3D0.7)
2. Find the area under the curve for each of the specified intervals:
(triangle with base 2 and height 0.2)
(triangle with base 1 and height 0.4)
(trapezoid with "bases" 0.2 and 0.4 and "height" 2)
(trapezoid with "bases" 0.1 and 0.3 and "height" 2)
Step-by-step explanation:
Here you solve for length width and height, which multiplied equal volume. The only constant you have is that the width of the prism is 1/3 of its length.
WIDTH: 3 centimeters
LENGTH: Since the width is 1/3 of the length, 3 is 1/3 of something. So divide 3 by 1/3 to get 9. You can also just multiply 3 by 3.
HEIGHT: The height is half of the width, which is 3. Therefore 3 divided by 2 is 1.5.
Now multiply the values. 3 multiplied by 9 multiplied by 1.5
The answer is 40.5
CENTIMETERS!!!
DO NOT FORGET THE UNIT
I really hope this can help you:)