Answer:
Step-by-step explanation:
191.2 = 2.3L +65.5
191.2 - 65.5 = 2.3L {Subtract 65.5 from both sides}
125.7= 2.3L
L = 125.7/2.3
L = 54.65
A. Western Beach is reducing was width by 10 feet every 5 years for the first 10 years, then the pattern became less constant. Dunes Beach experienced a stable and fast increase in width, 25 feet every 5 years of 5 feet per year.
B. Somewhere between years 11 and 12 they had the same width.
C. You can place the values on a graph and connect the points, and look at the intersections to determine points in time where they were of the same width.
First, lets look at the data. Western Beach (or WB for short) decreases its width by 10 feet every 5 years from year 0 to year 10. Between year 11 and year 15 the pattern shifts and becomes less changing since there is barely any change between years 12 and 15. Dunes Beach (or DB) increases steadily by 25 feet every 5 years or 5 feet per year.
Assuming the changes in width happen over time and gradually, at some point between year 10 and 11, both beaches would have likely had the same width, somewhere between 70 and 75.
To determine the exact point in time where they meet we would need to draw a graph, with the width in feet on the X axis and the year on the Y axis. Then we place all the pairs in the graph by their coordinates, and connect the points that correspond to each beach. We then see where the lines intersect and use mathematics to determine the values of X and Y, giving us the time and width when the two beaches were equal.
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Answer:
R=0.39789 ft
Step-by-step explanation:
For the perfectly mowed lawn, after one revolution, you want the lawnmower to be exactly one lawnmower's width closer to the pole. This implies that one lawnmower width should wrap around the circumference of the pole every revolution. So for this lawnmower we want:
2πR=2.5
⇒R=2.5/2π
R=0.39789 ft
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
