Yes the diagonals of a parallelogram have the same midpoint since they ... of the intersection of the diagonals of parallelogram AB CD given the vertex points ... If a parallelogram is a rhombus then its diagonals are? , statement 2 is the answer
Answer:2.5 m/s
Step-by-step explanation:
Answer:
Quadrant 4
Step-by-step explanation:
sinA < 0 in quadrants 3 and 4
cosA > 0 in quadrants 1 and 4
Thus sinA < 0 and cosA > 0 in quadrant 4
You know that three points A,B,CA,B,C (two vectors A⃗ BA→B, A⃗ CA→C) form a plane. If you want to show the fourth one DD is on the same plane, you have to show that it forms, with any of the other point already belonging to the plane, a vector belonging to the plane (for instance A⃗ DA→D).
Since the cross product of two vectors is normal to the plane formed by the two vectors (A⃗ B×A⃗ CA→B×A→C is normal to the plane ABCABC), you just have to prove your last vector A⃗ DA→D is normal to this cross product, hence the triple product that should be equal to 00:
A⃗ D⋅(A⃗ B×AC)=0
Answer:
Step-by-step explanation:
SInce she used 
of it we will divide 
by
