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olasank [31]
3 years ago
12

4. Corrupt professor Z has a class of 50 students. He needs to give exactly 10 A's. However five students already have a special

deal (they are professor Z's nephews and nieces) and will get A's for sure. How many ways can the 10 A's be distributed?
Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that the professor Z has a class of 50 students is corrupt.   However five students already have a special deal (they are professor Z's nephews and nieces) and will get A's for sure.

Thus out of 10 students 5A's are reserved

Remaining 5 can be distributed in

I 5 to any one of the 45, II to any one of the 44....

i.e. 45P5 ways

no of ways = 45P5 == 146611080

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Step-by-step explanation:

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Find thhe remainder when 7^203 is divided by 4
Aleksandr [31]
Using the square-and-multiply approach, we have

7^{203}=7\times(7^{101})^2
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and so, using the property that, if a_1\equiv b_1\mod n and a_2\equiv b_2\mod n, then a_1a_2\equiv b_1b_2\mod n, we get

7\equiv3\mod4
7^2\equiv9\equiv1\mod4
7^3\equiv7\times1\equiv7\equiv3\mod4
7^6\equiv9\equiv1\mod4
7^{12}\equiv1\mod4
7^{25}\equiv7\times1\equiv7\equiv3\mod4
7^{50}\equiv9\equiv1\mod4
7^{101}\equiv7\times1\equiv7\equiv3\mod4
7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4
4 0
3 years ago
Help me Guess just help please
Andrew [12]

Answer:

maybe 2 only?

Step-by-step explanation:

I'm just guessing but it sounds right

7 0
3 years ago
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The answer is B, the answer is 9,318,000= 9.318•10 to the 6th power
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4 years ago
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