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erica [24]
3 years ago
14

Plzz pls pls pls pls help me I’m stuck

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

1. x-5=3x-45

2. x=20

3.Perimeter is 45 units since each side is 15 units.

Step-by-step explanation:

x-5=3x-45

-5=2x-45

40=2x

x=20

So AB is 15 and AC and BC is also 15 since it is equilateral. 15+15+15=45 The perimeter is 45 units.

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8 0
3 years ago
Solve 3 -x = 243 -5 1/5 5
Paraphin [41]

Answer:

x=-243

Step-by-step explanation:

The equation is

-3^{-5}=\frac{1}{x}

Solve for x

we know that

-3^{-5}=-\frac{1}{3^{5}}=-\frac{1}{243}

substitute

-\frac{1}{243}=\frac{1}{x}

so

x=-243

3 0
4 years ago
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Brenna owns 9 T-shirts, 3 of which are red.
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Answer:

1/3

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5 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
I need help PLEASE!!!!!!!!
PIT_PIT [208]

Answer:

Step-by-step explanation:

<h2>the letter in the problem is the missing number</h2>
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4 years ago
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