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V125BC [204]
2 years ago
6

Please help me ASAP im struggling :(

Mathematics
1 answer:
erik [133]2 years ago
7 0

Answer:

The answer is C!!

Step-by-step explanation:

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Suppose there is a simple index of three stocks, stock X, stock Y, and stock Z.
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Answer:

C

Step-by-step explanation:

so the first one ends at 4.7107

the second- 3.3568

the third- 5.1401

and multiplying the first by 5000 we get- 23,553.5

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for the third we get 41,120

adding them all together we get 71,387.1

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A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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