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andrew-mc [135]
2 years ago
6

A right pyramid has a height of 3 inches and a square base with side length of 5 inches. What is the volume of the pyramid?

Mathematics
1 answer:
Julli [10]2 years ago
4 0

Answer: 25 in³

Step-by-step explanation:

We can calculate the volume of the pyramid by first calculating the volume of a prism with the same dimensions, and then dividing by 3 (all pyramids a volume that's \frac{1}{3} of the volume of a prism with the same dimensions).

The volume of a prism is its base area times its height. The base would be a square, so its area is 5², which is 25. The height is 3 inches, making the prism's volume 75 in³.

The volume of the pyramid would be one-third of this value, which is 7575\div3 which is 25 in³.

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ser-zykov [4K]

Answer: In my answer I got 9 because the formula to find the area it would be A=1/2b*h



Step-by-step explanation: How would you do this?

Well we know that the base equals 6 we have heighth so we would have to do 1.5*6 and that would give us 9 but if we round it would be 10 because 9 is closer to 10 than it is to 0.


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4 0
3 years ago
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Minchanka [31]
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3 years ago
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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




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choli [55]

Answer:

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Step-by-step explanation:

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3 years ago
Someone Please Help Me With This<br><br> n <br> _ = 1 6<br> 3
Ivahew [28]

Answer:

n=48

Step-by-step explanation:

n  

_ = 1 6

3

Multiply each side by 3

n/3 * 3 = 16*3

n = 48

3 0
3 years ago
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